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X^2+23X+60=630
We move all terms to the left:
X^2+23X+60-(630)=0
We add all the numbers together, and all the variables
X^2+23X-570=0
a = 1; b = 23; c = -570;
Δ = b2-4ac
Δ = 232-4·1·(-570)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-53}{2*1}=\frac{-76}{2} =-38 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+53}{2*1}=\frac{30}{2} =15 $
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